3-dimensional coordinate systems [9.1]

Locating objects in 3-dimensions.

  • Right-handed Cartesian coordinates
  • Points in 3-D space
  • Equations of planes
  • Distance formula in 3 dimensions
  • Equations of spheres

Rectangular coordinates

Also known as Cartesian coordinates, after Renes Descartes

Right-handed coordinate system

  1. Take your right hand...
  2. Point your straight fingers in the $\hat x$ direction.
  3. Rotate your hand so that you can curl your fingers* to point in the $\hat y$ direction.
  4. Your thumb now points in the $\hat z$ direction.

* You need to be able to curl your fingers through an angle less than $180^o$.

Try x and y, then x and z and y and z, and figure out which way the other axis points.

To Do

  • Create a set of coordinate axes [pipecleaners]
  • Do the Visualizing the xyz coordinate system worksheet (See the "handouts" folder):
    Write down which color is your $x$-axis, your $y$-axis, and your $z$-axis.

Coordinate planes

Coordinates

Projections

$S$ is the projection of $P$ onto the $xz$ plane.

$(0,b,0)$ is the projection of $P$ onto the $y$-axis.

The space $\mathbb{R}^3$

$\mathbb{R}\equiv$ the real numbers.

  • Cartesian Product:
    $\mathbb{R}^3\equiv \mathbb{R}\times\mathbb{R}\times\mathbb{R}=\{(x,y,z) | x,y,z\in \mathbb{R}\}$.
  • Set of all ordered triples.

To Do

  • Points in the xyz coordinate system worksheet

Surfaces in $\mathbb{R}^3$


All points with coordinates $(a,b,c)$ where $c=3$
[and $a$ and $b$ can be anything]



All points with coordinates $(x,y,z)$ where $y=x$.

Notice that $y=x$ is the definition of a line in 2-d with a slope of 1. But here??

Anything a bit deceptive about the picture above?

Should continue to values with x and y less than 0...

To Do

  • Section 9.1 Group Work: Fun with Visualization [missing]
  • Working with surfaces in 3D space [missing]

Distance

What is the distance $|P_1P_2|$ between two points $P_1(x_1,y_1,z_1)$ and $P_2(x_2,y_2,z_2)$ in three dimensional space?

With $\Delta x=x_2-x_1$, etc, you can imagine applying Pythagoras' theorem twice [at GeoGebra, 9.1.distance.nb]:

  • The blue line is the hypotenuse of the triangle with legs $\Delta x$ and $\Delta y$: It's length is $\sqrt{(\Delta x)^2+(\Delta y)^2}$.
  • The green line is our distance, and is the hypotenuse of the right triangle with legs of $\Delta z$ and the blue line.

So, our distance formula is: $$|P_1P_2|=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2+(z_2-z_1)^2}.$$

Equation of a sphere

All the points on a sphere are the same distance, $r$, away from its center, $C(h,k,l)$. Using the distance formula: $$(x-h)^2+(y-k)^2+(z-l)^2 = r^2.$$

These equations describe sets of points,$\{(x,y,z)\}$ that fulfill the equation equation. For each equation, make a guess at the surface corresponding to the equation, then check it by typing the equation into GeoGebra: [Hint, think about what the distance formula implies.]

  1. $$ 9=x^2+y^2+z^2.$$
  2. $$z=\sqrt{ 9-x^2-y^2}.$$
  3. $$9=x^2+y^2.$$

Problem 9.1.038

Consider a 2-d variation of this problem...Find all the points, $P$, (they form a circle) that are twice as far from $A$ as they are from $B$.

Well... It ought to be possible to find *some* of the points $P$. Consider these (leading) questions:

  1. How would you find the coordinates of a point which is halfway between $A$ and $B$?
  2. One of the points in the set $\{P\}$ should be on the line segment between $A$ and $B$. What fraction of the distance from $A$ to $B$ is that point?
  3. What are the coordinates of that point?
  4. There is one other point in $\{P\}$ along the red line, but not between $A$ and $B$. What fractional distance would it be? That is... if the distance from $A$ to $B$ were 1, what would the distance from $A$ to this second point be?
  5. Now we have a segment of the red line that connects two points on a circle. Either the line segment is a diameter line, or it is not. Can you make an argument for why the center of the circle could, or could not be away from the line segment?
  6. So, where is the center of the circle? And what is its radius?

    Image credits

    Mortimer